25x^2-45x-36=0

Solution for 25x^2-45x-36=0 equation:

25x^2-45x-36=0

a = 25; b = -45; c = -36;
Δ = b2-4ac
Δ = -452-4·25·(-36)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-75}{2*25}=\frac{-30}{50}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+75}{2*25}=\frac{120}{50}
=2+2/5
$